백준: 문자열분석 난이도: 브론즈2 #include #include #include #include using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); string str; int count = 0; vector v(101); while(getline(cin, str, '\n')) { if (count == 101) break; for(int i=0;i= 'a' && str[i] = 'A' && str[i] = '0' && str[i]