백준 10820 c++

백준: 문자열분석

난이도: 브론즈2

#include <iostream>
#include <algorithm>
#include <vector>
#include <string>

using namespace std;

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(NULL);
	cout.tie(NULL);

	string str;
	int count = 0;

	vector < pair<pair<int, int>, pair<int, int>>>v(101);

	while(getline(cin, str, '\n'))
	{	
		if (count == 101)
			break;

		for(int i=0;i<str.length();i++)
		{
			if (str[i] >= 'a' && str[i] <= 'z')
				v[count].first.first++;
			else if (str[i] >= 'A' && str[i] <= 'Z')
				v[count].first.second++;
			else if (str[i] >= '0' && str[i] <= '9')
				v[count].second.first++;
			else if (str[i] == ' ')
				v[count].second.second++;
		}
		cout << v[count].first.first << " " << v[count].first.second << " " << v[count].second.first << " " << v[count].second.second << "\n";

		count++;
	}

	return 0;
}